rangeRight (for BigInts) ​
Returns the same BigInts as range, but in descending order.
const numbers = rangeRight(end);
const numbers = rangeRight(start, end);
const numbers = rangeRight(start, end, step);INFO
This function is available exclusively from es-toolkit/bigint to avoid potential conflicts with similar functions for other numeric types.
Usage ​
rangeRight(end) ​
Use rangeRight with one argument to count down from just below the end value to 0n.
import { rangeRight } from 'es-toolkit/bigint';
console.log(rangeRight(4n)); // [3n, 2n, 1n, 0n]
console.log(rangeRight(0n)); // []Parameters ​
end(bigint): The end of the range, exclusive.
Returns ​
(bigint[]): Returns an array of BigInts from just below end down to 0n.
rangeRight(start, end) ​
Use rangeRight with two arguments to count down to a start value other than 0n.
import { rangeRight } from 'es-toolkit/bigint';
console.log(rangeRight(2n, 5n)); // [4n, 3n, 2n]
console.log(rangeRight(-3n, 0n)); // [-1n, -2n, -3n]Parameters ​
start(bigint): The start of the range, inclusive.end(bigint): The end of the range, exclusive.
Returns ​
(bigint[]): Returns an array of BigInts from just below end down to start.
rangeRight(start, end, step) ​
Use rangeRight with three arguments to step by something other than 1n. The values are exactly those of range with the same arguments, reversed.
import { range, rangeRight } from 'es-toolkit/bigint';
console.log(rangeRight(0n, 10n, 2n)); // [8n, 6n, 4n, 2n, 0n]
console.log(rangeRight(5n, 0n, -1n)); // [1n, 2n, 3n, 4n, 5n]
// Always the reverse of range with the same arguments
console.log(rangeRight(0n, 10n, 3n)); // [9n, 6n, 3n, 0n]
console.log(range(0n, 10n, 3n)); // [0n, 3n, 6n, 9n]If the step points away from the end value, there is nothing to produce and you get an empty array.
import { rangeRight } from 'es-toolkit/bigint';
console.log(rangeRight(0n, 5n, -1n)); // []Parameters ​
start(bigint): The start of the range, inclusive.end(bigint): The end of the range, exclusive.step(bigint, optional): The amount to count by. Defaults to1n.
Returns ​
(bigint[]): Returns the values of range(start, end, step) in descending order.
Throws ​
Throws an error if step is 0n.

